3x^2-100x+750=0

Solution for 3x^2-100x+750=0 equation:

3x^2-100x+750=0

a = 3; b = -100; c = +750;
Δ = b2-4ac
Δ = -1002-4·3·750
Δ = 1000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1000}=\sqrt{100*10}=\sqrt{100}*\sqrt{10}=10\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-10\sqrt{10}}{2*3}=\frac{100-10\sqrt{10}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+10\sqrt{10}}{2*3}=\frac{100+10\sqrt{10}}{6}
$